032 Laboratory Three: Accelerated Motion

Dropping the Ball on the Job

Introduction

This laboratory explores the relationship between time and distance for an object moving at a constant acceleration. In this situation the velocity is changing.

Goals

Theory

Existing gravitational theory asserts that the distance an object falls when dropped is given by the mathematical equation:

distance=12 gravity×time2

or

d=12 gt2

The theory predicts that graph of time versus distance should result in the half-curve of the start of a quadratic parabola as seen in graph 1.

Time versus space, space versus space graphs text layers Graph 1 Graph 2 time (s) [time (s)]² height d (cm) height d (cm)

This graph suggests that time and distance are not related linearily. That is, twice as much fall time results NOT in twice as much distance fallen, but in MORE THAN twice as much distance fallen. Look at the graph – a fall of 0.4 seconds falls about 80 cm, but 0.8 seconds falls over 300 cm. When the fall time doubles, the distance appears to QUADRUPLE.

Confirming the hypothesis that a time versus distance graph is a quadratic curve is difficult. We cannot determine the slope of a curve using a best fit straight line. The slope would be in centimeters per second (speed) but the slope is changing, the line is curved, which means the speed must of the falling object must be changing.

If the theory is correct and the relationship is a quadratic relationship ("x²"), then we can square the time values and graph these squared time values on the x-axis and the distance values on the y-axis. The result should be a straight line with a slope of one half g as seen in graph 2.

d=12 g[t2]

This is just like y = mx except that for x we are going to graph the square of the time [t²]. If all goes well, this second graph should be a straight line. The values on your axes will differ from those seen here.

The units of slope for the second graph and of gravity in this laboratory are centimeters per second squared, also written cm/s².

Note that your graphs based on your data from laboratory might not produce lines as smooth as those seen above. Small deviations from a smooth line are the result of small errors in measurement, not evidence that the theory is false. The whole pattern of the data would have to disagree with shape proposed to disconfirm the theory.

Bounce diagram meter stick start timer stop timer height d (distance)

Procedure

The theory above applies to a ball falling a distance d. The complication is that the duration of time a falling ball is in the air is very short. This is difficult to measure. We will take advantage of symmetry to increase the time intervals. The length of time for a ball to fall a distance d is the same as the time for a ball to rise to that height above the ground.

We will drop a ball, wait for the first bounce, and time the duration until the second bounce. During this time the ball will bounce up to a height we will call the distance d and fall back to the ground. This time can then be divided by two to obtain the time for the ball to fall from a height d.

Teams of five to six students will be formed composed of the following roles to facilitate measurements:

Small high bounce balls will be used. Practice dropping the ball and measuring the time between the first two bounces and determining the bounce height d. Note that by dropping the ball from the same height you can "repeat" the bounce height fairly accurately.

  1. Start by dropping the ball from one meter above the ground. Determine the duration of time in seconds between the first two bounces and the bounce height d in centimeters.
  2. Move up by 20 centimeters and drop the ball from 120 cm. Record the time between the first two bounces and the bounce height.
  3. Move up by another 20 centimeters and repeat the procedure. Continue going up by 20 centimeters until you reach 300 cm.

Notes

Data will be recorded into a table and then plotted on graph paper, using the mean time in seconds on the horizontal x axis and the drop height in centimeters on the vertical y axis.

For data analysis a second table will be prepared using the square of the time in seconds versus the drop distance. This data will also be plotted on a graph sheet.

Data tables [d] [t]

Graph these two columns:
If the theory holds, then the result is a parabola
Drop heightBounce timeFall time (s) [x]Bounce height (cm) [y]
100
120
140
160
180
200
220
240
260
380
300

Note that the fall time is half the bounce time. Divide the bounce time by two to get the fall time.

Graph the x versus y data for the above table but do not try to calculate the slope. If the theory is correct, then the graph should be a gentle curve with a parabolic shape. Remember – includes units in the header cells of the table. Do not put units in the data cells of the table in a spreadsheet. The "letters" will cause a spreadsheet to fail to graph the data as xy scattergraph data.

Data analysis and results

Use your calculator to square the fall times in the table above and record the results below.

Graph these two columns. if the theory holds, then this data should plot as a straight line
fall time² [x²] (s²)
put the square of the mean drop time values in this column!
Bounce height (cm) [y]

Plot the data in this table. Make sure your axes are laid out with scales where equal distances are equal changes in values along that scale.

Calculating the slope and intercept with calculators

Some calculators can perform a linear regression. Your instructor will assist groups with determining the slope and intercept for their data using their calculators.

Using a calculator determine the slope of the line for the time squared versus distance data. Note that we are calculating the slope m for the quadratic equation y = mx² because our data table is using the square of the x-values.

Thus the slope m is equal to half of the acceleration of gravity g. We can multiply our slope by two to calculate the acceleration of gravity for our ball drop.

slope m=12g therefore g=2×slope m

On the second graph the rise is centimeters and the run is seconds². Slope is rise over run. Therefore the units of slope and of the acceleration of gravity are cm/s².

Use your g and the formula d=12 gt2 to predict the fall time t for a drop d of 500 centimeters.

The "textbook" value for the acceleration of gravity g at earth's surface is 980 cm/s². How close did you come to this result? Calculate (your value of g − 980)/980 to determine the percentage difference between your g and the value quoted in science texts. [a]

Data Display: Graphs [g] [g]

For data display two graphs are required. The first graph will depict time versus distance, the second will plot the time squared against the distance. Use a spreadsheet to generate these graphs and then copy and paste the graphs into a word processor for your report.

Conclusion [c]

Discuss the nature of the mathematical relationship between time and distance for a falling object. Discuss whether the first graph could be parabolic, allowing for the uncertainty the small errors that may cause the points to "wiggle" slightly. Discuss whether the second graph is a line. Report the slope m and the calculation for the acceleration of gravity g. You can compare your result to the textbook result of 980 cm/s² Discuss any problems you encountered in this laboratory including those that may have contributed to uncertainty in your measurements.